1)
[tex]2\dfrac{2}{3}-2\dfrac{2}{5}=2\dfrac{2\cdot5}{3\cdot5}-2\dfrac{2\cdot3}{5\cdot3}=2\dfrac{10}{15}-2\dfrac{6}{15}=\boxed{\frac{4}{15}}\\[/tex]
2)
[tex]3\dfrac{4}{9}-2\dfrac{2}{5}=3\dfrac{4\cdot5}{9\cdot5}-2\dfrac{2\cdot9}{5\cdot9}=3\dfrac{20}{45}-2\dfrac{18}{45}=\boxed{1\frac{2}{25}}\\[/tex]
3)
[tex]4\dfrac{5}{8}-2\dfrac{2}{5}=4\dfrac{5\cdot5}{8\cdot5}-2\dfrac{2\cdot8}{5\cdot8}=4\dfrac{25}{40}-2\dfrac{16}{40}=\boxed{2\frac{9}{40}}\\[/tex]
4)
[tex]3\dfrac{2}{7}-2\dfrac{2}{5}=3\dfrac{2\cdot5}{7\cdot5}-2\dfrac{2\cdot7}{5\cdot7}=3\dfrac{10}{35}-2\dfrac{14}{35}=2\dfrac{45}{35}-2\dfrac{14}{35}=\boxed{\frac{31}{35}}\\[/tex]
5)
[tex]5\dfrac{1}{6}-2\dfrac{2}{5}=5\dfrac{1\cdot5}{6\cdot5}-2\dfrac{2\cdot6}{5\cdot6}=5\dfrac{5}{30}-2\dfrac{12}{30}=4\dfrac{35}{30}-2\dfrac{12}{30}=\boxed{2\frac{23}{30}}\\[/tex]
6)
[tex]6\dfrac{3}{10}-2\dfrac{2}{5}=6\dfrac{3}{10}-2\dfrac{2\cdot2}{5\cdot2}=6\dfrac{3}{10}-2\dfrac{4}{10}=5\dfrac{13}{10}-2\dfrac{4}{10}=\boxed{3\frac{9}{10}}\\[/tex]
