Odpowiedź:
[tex]1.\\\\7(x+2)-\frac{1}{4}=\frac{3}{4}(x-4)+3\\\\7x+14-\frac{1}{4}=\frac{3}{4}x-3+3\\\\7x+14-\frac{1}{4}=\frac{3}{4}x\ \ /\cdot4\\\\28x+56-1=3x\\\\28x+55=3x\\\\28x-3x=-55\\\\25x=-55\ \ /:25\\\\x=-\frac{55}{25}\\\\x=-\frac{11}{5}\\\\x=-2\frac{1}{5}\\\\\\2.\\\\0,6(x+2)-(0,4x-0,6)=0,2(1-x)\\\\0,6x+1,2-0,4x+0,6=0,2-0,2x\\\\0,2x+1,8=0,2-0,2x\\\\0,2x+0,2x=0,2-1,8\\\\0,4x=-1,6\ \ /:0,4\\\\x=-4[/tex]
[tex]3.\\\\2(x+\frac{1}{2})-\frac{2}{3}(3-6x)=x+2\\\\2x+1-2+4x=x+2\\\\6x-1=x+2\\\\6x-x=2+1\\\\5x=3\ \ /:5\\\\x=\frac{3}{5}\\\\\\4.\\\\5x-6(x+7)=8x-9(10+x)\\\\5x-6x-42=8x-90-9x\\\\-x-42=-x-90\\\\-x+x=-90+42\\\\0=-48\\\\R\'ownanie\ \ sprzeczne\ \ nie\ \ ma\ \ rozwiazania[/tex]
[tex]5.\\\\0,1(x-10)-0,6x=1,5x-4\\\\0,1x-1-0,6x=1,5x-4\\\\-0,5x-1=1,5x-4\\\\-0,5x-1,5x=-4+1\\\\-2x=-3\ \ /:(-2)\\\\x=\frac{3}{2}\\\\x=1\frac{1}{2}[/tex]
