Odpowiedź:
Szczegółowe wyjaśnienie:
([tex]a)(\frac{1}{6})^{-1}=\frac{6}{1} ^{1} =6\\b)(\frac{1}{4}) ^{-2} =\frac{4}{1} ^{2} =16\\c)(\frac{3}{5})^{-3} =\frac{5}{3} ^{3} =\frac{125}{27} \\d)(\frac{4}{3}) ^{-4}=\frac{3}{4} ^{4} =\frac{81}{256} \\e)(-\frac{3}{2})^{-3}=(-\frac{2}{3})^{3} =-\frac{8}{27}\\f)(-1\frac{3}{4})^{-1} =(-\frac{7}{4} )^{-1}=(\frac{4}{7})^{1}=-\frac{4}{7} \\g)(-\frac{4}{9})^{-2} =(\frac{9}{4}) ^{2}=\frac{81}{16} \\h)(-3\frac{1}{3})\x^{-4} =(-\frac{9}{4})^{-4} =(-\frac{1}{9} )^{4} =\frac{1}{6561}[/tex]
