Podpunkt a)
[tex]2\dfrac{5}{7}=\dfrac{2\cdot7+5}{7}=\dfrac{14+5}{7}=\boxed{\frac{19}{7}}\\\\\\2\dfrac{7}{8}=\dfrac{2\cdot8+7}{8}=\dfrac{16+7}{8}=\boxed{\frac{23}{8}}\\\\\\2\dfrac{3}{10}=\dfrac{2\cdot10+3}{10}=\dfrac{20+3}{10}=\boxed{\frac{23}{10}}[/tex]
Podpunkt b)
[tex]5\dfrac{1}{3}=\dfrac{5\cdot3+1}{3}=\dfrac{15+1}{3}=\boxed{\frac{16}{3}}\\\\\\5\dfrac{8}{11}=\dfrac{5\cdot11+8}{11}=\dfrac{55+8}{11}=\boxed{\frac{63}{11}}\\\\\\5\dfrac{4}{15}=\dfrac{5\cdot15+4}{15}=\dfrac{75+4}{15}=\boxed{\frac{79}{15}}[/tex]
Podpunkt c)
[tex]6\dfrac{4}{7}=\dfrac{6\cdot7+4}{7}=\dfrac{42+4}{7}=\boxed{\frac{46}{7}}\\\\\\6\dfrac{5}{9}=\dfrac{6\cdot9+5}{9}=\dfrac{54+5}{9}=\boxed{\frac{59}{9}}\\\\\\6\dfrac{13}{15}=\dfrac{6\cdot15+13}{15}=\dfrac{90+13}{15}=\boxed{\frac{103}{15}}[/tex]
