Odpowiedź:
b, c, a
Szczegółowe wyjaśnienie:
[tex]a=\dfrac{1-0,125\cdot\frac12}{\frac78-\frac34}=\dfrac{1-\frac18\cdot\frac12}{\frac78-\frac68}=\dfrac{1-\frac1{16}}{\frac18}=\dfrac{\frac{15}{16}}{\frac18}=\frac{15}{16}\cdot\frac81=\frac{15}2=7,5[/tex]
[tex]b=1\frac{1}{2}\cdot4\frac6{11}\cdot3\frac23\cdot(-\frac15)=\frac{3}{2}\cdot\frac{50}{11}\cdot\frac{11}3\cdot(-\frac15)=\frac11\cdot\frac{25}{1}\cdot\frac{1}1\cdot(-\frac15)=-\frac{25}5=-5[/tex]
[tex]c=\frac2{11}\cdot1,5\cdot2,74\cdot(-1\frac13)=\frac2{11}\cdot\frac32\cdot2\frac34\cdot(-\frac43)=-\frac1{11}\cdot\frac31\cdot\frac{11}4\cdot\frac43=-1[/tex]
[tex]-5\, <\, -1\, <\, 7,5\quad\implies\quad b\,<\,c\,<\,a[/tex]
