Odpowiedź:
[tex](\sqrt{2}-4)^3=(\sqrt{2})^3-3\cdot(\sqrt{2})^2\cdot4+3\sqrt{2}\cdot4^2-4^3=\sqrt{8}-3\cdot2\cdot4+3\sqrt{2}\cdot16-64=\\\\=\sqrt{4\cdot2}-24+48\sqrt{2}-64=2\sqrt{2}-24+48\sqrt{2}-64=50\sqrt{2}-88\\\\\\Zastosowano\ \ wz\'or\\\\(a-b)^3=a^3-3a^2b+3ab^2-b^3[/tex]
