Odpowiedź :
1.
[tex]Dane:\\v_{o} = 0\\a = 1,5\frac{m}{s^{2}}\\v = 4,5\frac{m}{s}\\Szukane:\\t = ?\\\\v = a\cdot t \ \ /:a\\\\t = \frac{v}{a}\\\\t = \frac{4,5\frac{m}{s}}{1,5\frac{m}{s^{2}}}\\\\\boxed{t = 3 \ s}[/tex]
2.
[tex]Dane:\\v_{o} = 0\\t = 5,2 \ s\\v = 200\frac{km}{h} = 200\cdot\frac{1000 \ m}{3600 \ s} = 55,(5)\frac{m}{s} \approx5,56\frac{m}{s}\\Szukane:\\a = ?\\\\a = \frac{\Delta v}{t} = \frac{v}{t}\\\\a = \frac{55,56\frac{m}{s}}{5,2 \ s}\\\\\boxed{a\approx10,68\frac{m}{s^{2}}}[/tex]
3.
[tex]Dane:\\v_{o} = 0\\t = 2 \ s\\a = g = 10\frac{m}{s^{2}}\\Szukane:\\a) \ v = ?\\b) \ h = ?\\\\a)\\v = g\cdot t\\\\v = 10\frac{m}{s^{2}}\cdot2 \ s\\\\\boxed{v = 20\frac{m}{s}}[/tex]
[tex]b)\\h = \frac{1}{2}gt^{2}}\\\\h = \frac{1}{2}\cdot10\frac{m}{s^{2}}\cdot(2 \ s)^{2}\\\\\boxed{h = 20 \ m}[/tex]
4.
[tex]Dane:\\v_{o} = 18\frac{m}{s}\\t = 3 \ s\\a = 2\frac{m}{s^{2}}\\Szukane:\\v = ?\\\\v = v_{o}-at\\\\v = 18\frac{m}{s}-2\frac{m}{s^{2}}\cdot3 \ s\\\\v = 18\frac{m}{s}-6\frac{m}{s}\\\\\boxed{v = 12\frac{m}{s}}[/tex]