proszę o rozwiązanie

[tex]\left(\frac{4}{5}\right)^{-7x-3}=\left(\frac{5}{4}\right)^{-5x+2}\\\\\left(\frac{5}{4}\right)^{-(-7x-3)}=\left(\frac{5}{4}\right)^{-5x+2}\\\\-(-7x-3)=-5x+2\\\\7x+3=-5x+2\\\\7x+5x=2-3\\\\12x=-1\ \ \ |:12\\\\x=-\frac{1}{12}[/tex]