Witaj :)
[tex]\frac{(3^{15}+3^{13})\cdot 2^9}{(3^{14}+3^{12})\cdot 1024}=\frac{(3^{15}+3^{13})\cdot 2^9}{(3^{14}+3^{12})\cdot 2^{10}}=\frac{3^{15}+3^{13}}{3^{14}+3^{12}} \cdot \frac{2^9}{2^{10}}= \frac{3^{13}(3^2+1)}{3^{12}(3^2+1)} \cdot \frac{2^9}{2^{10}}=\\\\=\frac{3^{13}}{3^{12}} \cdot \frac{2^9}{2^{10}}=3^{13-12}\cdot 2^{9-10}=3^1\cdot 2^{-1}=3\cdot \frac{1}{2}=\frac{3}{2}=\boxed{1\frac{1}{2} }[/tex]
