Odpowiedź:
[tex]c)\\\\\dfrac{3}{4}\cdot2\dfrac{1}{3}=\dfrac{\not3}{4}\cdot\dfrac{7}{\not3}=\dfrac{7}{4}=1\dfrac{3}{4}\\\\\\3\dfrac{1}{3}\cdot\dfrac{2}{10}=\dfrac{\not10^2}{3}\cdot\dfrac{1}{\not5_{1}}=\dfrac{2}{3}\\\\\\\\d)\\\\1\dfrac{2}{3}\cdot1\dfrac{4}{5}=\dfrac{\not5^1}{\not3_{1}}\cdot\dfrac{\not9^3}{\not5_{1}}=3\\\\\\2\dfrac{1}{4}\cdot1\dfrac{3}{5}=\dfrac{9}{\not4_{1}}\cdot\dfrac{\not8^2}{5}=\dfrac{18}{5}=3\dfrac{3}{5}[/tex]
