Odpowiedź :
Cześć!
a)
[tex]A=(2,3)\Rightarrow x_A=2, \ y_A=3\\\\B=(4,3)\Rightarrow x_B=4, \ y_B=3\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\\\|AB|=\sqrt{(4-2)^2+(3-3)^2}\\\\|AB|=\sqrt{2^2+0^2}\\\\|AB|=\sqrt{2^2}\\\\\huge\boxed{|AB|=2}[/tex]
b)
[tex]C=(-4,1)\Rightarrow x_C=-4, \ y_C=1\\\\D=(-4,-4)\Rightarrow x_D=-4, \ y_D}=-4\\\\|CD|=\sqrt{(x_D-x_C)^2+(y_D-y_C)^2}\\\\|CD|=\sqrt{(-4-(-4))^2+(-4-1)^2}\\\\|CD|=\sqrt{(-4+4)^2+(-5)^2}\\\\|CD|=\sqrt{0^2+25}=\sqrt{25}\\\\\huge\boxed{|CD|=5}[/tex]