[tex]\text{Zad. 1}\\\\\dfrac{1}{4\,\Omega}+\dfrac{1}{12\,\Omega}+\dfrac{1}{R_3}=\dfrac{1}{2,4\,\Omega}\\\\\dfrac{3}{12\,\Omega}+\dfrac{1}{12\,\Omega}+\dfrac{1}{R_3}=\dfrac{5}{12\,\Omega}\\\\\dfrac{4}{12\,\Omega}+\dfrac{1}{R_3}=\dfrac{5}{12\,\Omega}\\\\\dfrac{1}{R_3}=\dfrac{1}{12\,\Omega}\\\\R_3=12\,\Omega\\\\\text{Zad. 2}\\I_{wp}=I_{wy}\\I_{wp}=0,08\,\text{kA}+700\,\text{mA}+30\,\text{A}\\I_{wp}=80\,\text{A}+0,7\,\text{A}+30\,\text{A}\\I_{wp}=110,7\,\text{A}[/tex]
