[tex]\frac12:\frac13=\frac12*3=\frac32=1,5\\\\\frac12*x=4 /*2\\x=8\\\\4-x=1,5 \\4-1,5=x\\2,5=x\\\\x*\frac5{24}=\frac12 /*(\frac{24}5)\\x=\frac12*\frac{24}5\\x=\frac{12}5=\frac{24}{10}=2,4 - \text{lewy dolny rog}\\\\1,5+x=2,4\\x=2,4-1,5\\x=0,9 - \text{drugie puste pole, przy lewym dolnym rogu}[/tex]
