[tex]Dane:\\l = 200 \ m = 0,2 \ km \ - \ dlugosc \ pociagu\\L = 1,3 \ km \ - \ dlugosc \ tunelu\\s = l+L = 0,2 \ km + 1,3 \ km = 1,5 \ km\\t = 1,5 \ min = \frac{1,5}{80} \ h = 0,025 \ h\\Szukane:\\v = ?\\\\v = \frac{s}{t}\\\\v = \frac{1,5 \ km}{0,025 \ h}\\\\\boxed{v = 60\frac{km}{h}}[/tex]
