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[tex]1\frac{6}{7}-1\frac{3}{4}+\frac{1}{4}=1\frac{6}{7}-(1\frac{3}{4}-\frac{1}{4})=1\frac{6}{7}-1\frac{2}{4}=\\\\=1\frac{6}{7}-1\frac{1}{2}=1\frac{6\cdot2}{7\cdot2}-1\frac{1\cdot7}{2\cdot7}=1\frac{12}{14}-1\frac{7}{14}=\frac{5}{14}[/tex]
