Zastosujmy twierdzenie Pitagorasa
a)
[tex] {a}^{2} + {9}^{2} = {15}^{2} \\ {a}^{2} + 81 = 225 \\ {a}^{2} = 144 \\ a = \sqrt{144} \\ a = 12[/tex]
b)
[tex]( \sqrt{7} )^{2} + ( 2 \sqrt{5})^{2} = {b}^{2} \\ 7 + 4 \times 5 = {b}^{2} \\ 7 + 20 = {b}^{2} \\ {b}^{2} = 27 \\ b = \sqrt{27} \\ b = \sqrt{9 \times 3} \\ b = 3 \sqrt{3} [/tex]
Myślę że pomogłem ;)
