a)
[tex] \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{6}{12} + \frac{4}{12} + \frac{3}{12} = \frac{13}{12} = 1\frac{1}{12} [/tex]
b)
[tex]1 \frac{2}{5} + 3 \frac{4}{10} + 2 \frac{1}{2} = 1 \frac{4}{10} + 3 \frac{4}{10} + 2 \frac{5}{10} = 6 \frac{13}{10} = 7 \frac{3}{10} [/tex]
c)
[tex]4 \frac{1}{3} - 2 \frac{2}{5} + 1 \frac{1}{5} = 4 \frac{5}{15} - 2 \frac{6}{15} + 1 \frac{3}{15} =1 \frac{14}{15} + 1 \frac{3}{15} = 2 \frac{17}{15} = 3 \frac{2}{15} [/tex]
d)
[tex]7 - 3 \frac{1}{3} - 2 \frac{1}{8} = 3 \frac{2}{3} - 2 \frac{1}{8} = 3 \frac{16}{24} - 2 \frac{3}{24} = 1 \frac{13}{24} [/tex]
e)
[tex]3 \frac{3}{4} - 2 \frac{2}{3} + 6 - 3 \frac{5}{6} = 3 \frac{9}{12} - 2 \frac{8}{12} + 6 - 3 \frac{10}{12} = 1 \frac{1}{12} + 6 - 3 \frac{10}{12} = 7 \frac{1}{12} - 3 \frac{10}{12} = 6 \frac{13}{12} - 3 \frac{10}{12} = 3 \frac{3}{12} = 3 \frac{1}{4} [/tex]
f)
[tex]10 - (2 \frac{1}{9} - \frac{1}{2} + 1 \frac{5}{6} ) = 10 - (2 \frac{2}{18} - \frac{9}{18} + 1 \frac{15}{18}) = 10 - (1 \frac{20}{18} - \frac{9}{18} + 1 \frac{15}{18} ) = 10 - (1 \frac{11}{18} + 1 \frac{15}{18} ) = 10 - 2 \frac{26}{18} = 10 - 3 \frac{8}{18} = 6 \frac{10}{18} = 6 \frac{5}{9} [/tex]
Myślę że pomogłem ;)
