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[tex](5\frac{1}{2}-3\frac{1}{4})^2:7=(5\frac{1\cdot2}{2\cdot2}-3\frac{1}{4})^2:7=(5\frac{2}{4}-3\frac{1}{4})^2:7=\\\\=(2\frac{1}{4})^2:7=(\frac{2\cdot4+1}{2})^2:7=(\frac{8+1}{4})^2:7=(\frac{9}{4})^2:7=\\\\=\frac{9^2}{4^2}:7=\frac{9\cdot9}{4\cdot4}:7=\frac{81}{16}:7=\frac{81}{16}\cdot\frac{1}{7}=\frac{81}{112}[/tex]
