Cześć!
Rozwiązanie równania
[tex](\frac{2}{3})^x=2,25\\\\(\frac{2}{3})^x=2\frac{25}{100}\\\\(\frac{2}{3})^x=2\frac{1}{4}\\\\(\frac{2}{3})^x=\frac{9}{4}\\\\(\frac{2}{3})^x=(\frac{3}{2})^2\\\\(\frac{2}{3})^x=((\frac{2}{3})^{-1})^2\\\\(\frac{2}{3})^x=(\frac{2}{3})^{-2}\\\\\boxed{x=-2}[/tex]
