Odpowiedź:
d)
[tex] logx = \frac{1}{3} \\ log_{10}x = \frac{1}{3} \\ x = {10}^{ \frac{1}{3} } \\ x = \sqrt[3]{10} [/tex]
g)
[tex] log_{4}x = - 1 \\ x = {4}^{ - 1 } \\ x = \frac{1}{4} [/tex]
h)
[tex] log_{ \frac{1}{2} }x = 4 \\ x = (\frac{1}{2} ) {}^{4} \\ x = \frac{1}{16} [/tex]