Odpowiedź:
[tex]1\dfrac{5}{6}\cdot2\dfrac{4}{7}=\dfrac{11}{\not6_{1}}\cdot\dfrac{\not18^3}{7}=\dfrac{11\cdot3}{7}=\dfrac{33}{7}=4\dfrac{5}{7}\\\\\\2\dfrac{1}{2}\cdot3\dfrac{2}{8}=\dfrac{5}{2}\cdot3\dfrac{1}{4}=\dfrac{5}{2}\cdot\dfrac{13}{4}=\dfrac{65}{8}=8\dfrac{1}{8}\\\\\\1\dfrac{7}{20}\cdot2\dfrac{2}{9}=\dfrac{\not27^3}{\not20_{1} }\cdot\dfrac{\not20^1}{\not9_{1}}=3[/tex]
[tex]4\dfrac{8}{11}\cdot5\dfrac{2}{4}=\dfrac{52}{11}\cdot5\dfrac{1}{2}=\dfrac{\not52^2^6}{\not11_{1}}\cdot\dfrac{\not11^1}{\not2_{1}}=26[/tex]
