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Obliczenia
[tex]a=\sqrt[3]{216}+\sqrt{144}-2=\sqrt[3]{6^3}+\sqrt{12^2}-2=6+12-2=6+10=16\\\\b=\frac{33}{2,75:(\frac{1}{2}:\frac{1}{6})}=\frac{33}{2,75:(\frac{1}{2}\cdot6)}=\frac{33}{2,75:3}=\frac{33}{2\frac{3}{4}:3}=\frac{33}{\frac{11}{4}\cdot\frac{1}{3}}=\frac{33}{\frac{11}{12}}=33\cdot\frac{12}{11}=3\cdot12=36\\\\\frac{b}{a}\cdot100\%=\frac{36}{16}\cdot100\%=2,25\cdot100\%=\boxed{225\%}[/tex]
Odp. Liczba b stanowi 225% liczby a.
