Odpowiedź:
[tex]a)\ \ (2\frac{1}{2})^2=(\frac{5}{2})^2=\frac{5^2}{2^2}=\frac{25}{4}=6\frac{1}{4}\\\\\\b)\ \ (-1\frac{1}{3})^3-4^2=(-\frac{4}{3})^3-16=-\frac{4^3}{3^3}-16=-\frac{64}{27}-16=-2\frac{10}{27}-16=-18\frac{10}{27}[/tex]
[tex]c)\ \ \dfrac{[4\frac{3}{4}-(-2\frac{3}{5})]:2\frac{5}{8}}{-0,7}=\dfrac{(4\frac{3}{4}+2\frac{3}{5}):\frac{21}{8}}{-0,7}=\dfrac{(4\frac{15}{20}+2\frac{12}{20}):\frac{21}{8} }{-0,7}=\dfrac{6\frac{27}{20}:\frac{21}{8}}{-0,7}=\\\\\\=\dfrac{\frac{\not147^7}{\not20_{5} }\cdot\frac{\not8^2}{\not21_{1}}}{-0,7}=\dfrac{\frac{14}{5}}{-\frac{7}{10}}=-\frac{14}{5}:\frac{7}{10}=-\frac{\not14^2}{\not5_{1}}\cdot\frac{\not10^2}{\not7_{1}}=-2\cdot2=-4[/tex]
