Odpowiedź:
[tex]x-2(x+4)>3-x\\x-2x-8>3-x\\x-2x+x>3+8\\2x>11\\x>5.5\\\\2-4x:3>-2x+\frac{1}{4}\\2-\frac{4}{3} x > -2x + \frac{1}{4}\\-\frac{4}{3} x +2x > \frac{1}{4} - 2\\\frac{2}{3}x > \frac{7}{4} |*3\\2x > \frac{21}{4} | :2\\x > 2\frac{5}{8}[/tex]
