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[tex]\frac{\sqrt{80}}{\sqrt5}=\sqrt{\frac{80}{5}}=\sqrt{16}=4 \ (bo \ 4^2=4\cdot4=16)\\\\\frac{\sqrt8}{\sqrt2}=\sqrt{\frac{8}{2}}=\sqrt4=2 \ (bo \ 2^2=2\cdot2=4)[/tex]
