Odpowiedź:
[tex]\dfrac{6x^4(5x^4y^3)^3}{25(x^7y^2)^2xy^3}=\dfrac{6x^4\cdot5^3\cdot(x^4)^3\cdot(y^3)^3}{25\cdot(x^7)^2\cdot(y^2)^2\cdot xy^3}=\dfrac{6x^4\cdot\not125x^1^2y^9}{\not25x^1^4y^4xy^3}=\dfrac{6x^4\cdot5x^1^2y^9}{x^{14}y^4xy^3}=\\\\\\=\dfrac{30x^1^6y^9}{x^1^5y^7}=30x^{16-15}\cdot y^{9-7}=30xy^2\\\\\\dla\ \ x=333\ \ i\ \ y=2\\\\30xy^2=30\cdot333\cdot2^2=9990\cdot4=39960\\\\Odp.Warto\'s\'c\ \ wyra\.zenia\ \ wynosi\ \ 39960[/tex]
