Odpowiedź :
[tex]Dane:\\v = 13,8\frac{m}{s}\\g = 9,81\frac{m}{s^{2}}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\Z \ zasady \ zachowania \ energii\\\\E_{p} = E_{l}\\\\mgh = \frac{mv^{2}}{2} \ \ /:m\\\\gh = \frac{v^{2}}{2} \ \ /:g\\\\h = \frac{v^{2}}{2g}\\\\h = \frac{(13,8\frac{m}{s})^{2}}{2\cdot9,81\frac{m}{s^{2}}}=\frac{190,44\frac{m^{2}}{s^{2}}}{19,62\frac{m}{s^{2}}}\\\\\boxed{h \approx9,7 \ m}[/tex]
Odpowiedź:
v=13,8m/s
g=9,81m/s²
t=v/g
h=gt²/2
h=g(v/g)²/2
h=v²/2g
h=13,8²/2*9,81
h=9,71m