Odpowiedź :
Z Pitagorasa:
[tex](3\sqrt{5}) ^{2} } = (3\sqrt{3}) ^{2} } + x^{2} \\45=27+x^{2} \\x=\sqrt{18} \\\\P : \sqrt{18} * \sqrt{18} =18[/tex]
Z Pitagorasa:
[tex](3\sqrt{5}) ^{2} } = (3\sqrt{3}) ^{2} } + x^{2} \\45=27+x^{2} \\x=\sqrt{18} \\\\P : \sqrt{18} * \sqrt{18} =18[/tex]