[tex]\sqrt[7]{25}=25^{\frac{1}{7}}=(5^2)^{\frac{1}{7}}=5^{2\cdot\frac{1}{7}}=5^{\frac{2}{7}}\\\\\frac{1}{ \sqrt[4]{5 {}^{3} } }=\frac{1}{(5^3)^{\frac{1}{4}}}=\frac{1}{5^{\frac{3}{4}}}=5^{-\frac{3}{4}}\\\\5 \times \sqrt[3]{5}=5\cdot5^{\frac{1}{3}}=5^{1+\frac{1}{3}}=5^{1\frac{1}{3}}[/tex]
