Zastosujmy twierdzenie Pitagorasa
a)
[tex] {9}^{2} + {12}^{2} = {a}^{2} \\ 81 + 144 = {a}^{2} \\ 225 = {a}^{2} \\ a = \sqrt{225} \\ a = 15[/tex]
b)
[tex] {12}^{2} + {5}^{2} = {b}^{2} \\ 144 + 25 = {b}^{2} \\ 169 = {b}^{2} \\ b = \sqrt{169} \\ b = 13[/tex]
c)
[tex] {6}^{2} + {5}^{2} = {c}^{2} \\ 36 + 25 = {c}^{2} \\ 61 = {c}^{2} \\ c = \sqrt{61} [/tex]
d)
[tex] {6}^{2} + {d}^{2} = {10}^{2} \\ 36 + {d}^{2} = 100 \\ {d}^{2} = 64 \\ d = \sqrt{64} \\ d = 8 [/tex]
e)
[tex] {e}^{2} + ( \sqrt{11} )^{2} = {5}^{2} \\ {e}^{2} + 11 = 25 \\ {e}^{2} = 14 \\ e = \sqrt{14} [/tex]
f)
[tex] {f}^{2} + ( \sqrt{6} )^{2} = ( \sqrt{10} )^{2} \\ {f}^{2} + 6 = 10 \\ {f}^{2} = 4 \\ f = \sqrt{4} \\ f = 2[/tex]
Myślę że pomogłem ;)
