zad 2 i 3, twierdzenie pitagorasa

Twierdzenie Pitagorasa:
a^2 + b^2 = c^2
Zadanie 2
a) 5^2 + 4^2 = x^2
25 + 16 = x^2
41 = x^2
x = [tex]\sqrt{41}[/tex]
b) 1^2 + y^2 = 5[tex]\sqrt{2}[/tex]^2
25 * 2 - 1 = y^2
50 - 1 = y^2
y^2 = 49
y = [tex]\sqrt{49} = 7[/tex]
c) 4^2 + z^2 = 7^2
49 - 16 = z^2
33 = z^2
z = [tex]\sqrt{33}[/tex]
Zadanie 3
a) 15^2 + a^2 = 17^2
289 - 225 = a^2
a^2 = 64
a = [tex]\sqrt{64} = 8[/tex]
b) 3^2 + 4[tex]\sqrt{10}[/tex]^2 = b^2
9 + 16 * 10 = b^2
b^2 = [tex]\sqrt{169} = 13[/tex]