Odpowiedź:
[tex]a)\ \ 6(-x)\cdot y^2\cdot2(-y)\cdot x^3y=-6xy^2\cdot(-2y)\cdot x^3y=12xy^3\cdot x^3y=12x^4y^4\\\\b)\ \ -\frac{4}{5}abc^2\cdot1\frac{2}{3}a^3bc^4=-\frac{4}{\not5}abc^2\cdot\frac{\not5}{3}a^3bc^4=-\frac{4}{3}a^4b^2c^6[/tex]
