Odpowiedź:
mH2O= 2u+ 16u= 18u
mH2SO4= 2u+ 32u+ 4×16u= 2u+ 32u+ 64u= 98u
m= Ni2SO3= 2× 59u+ 32u+ 3×16u= 118u+ 32u+ 48u= 198u
mCa(OH)2= 40u+ 2× 16u+ 2u= 40u+ 32u+ 2u= 74u
m2CuSO4= 2× 64u+ 2× 32u+ 8× 16u= 128u+ 64u+ 128u= 320u
m3Na2O= 6× 23u+ 3× 16u= 138u+ 48u= 186u
m3Fe2(SO4)3= 6× 56u+ 9× 32u+ 36× 16u= 336u+ 288u+ 576u= 1200u
m2Cr(OH)3= 2× 52u+ 6× 16u+ 6u=104u + 96u+ 6u= 206u
m4Al(NO)3= 4+ 27u+ 12× 14u+ 12× 16u= 94u+ 168u+ 192u= 454u
m2CH3COOH= 4× 12u+ 8u+ 4× 16u= 48u+ 8u+ 64u= 120u
Wyjaśnienie:
