Odpowiedź:
[tex]-6y=14-13\frac{11}{17}\\\\-6y=13\frac{17}{17}-13\frac{11}{17}\\\\-6y=\frac{6}{17}\ \ |:(-6)\\\\y=\frac{\not6}{17}\cdot(-\frac{1}{\not6})\\\\y=-\frac{1}{17}[/tex]
