[tex]Dane:\\S = 0,5 \ m^{2}\\h = 60 \ cm = 0,6 \ m\\d = 1000\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\F_{n} = ?[/tex]
Rozwiązanie
Ciśnienie hydrostatyczne:
[tex]p = d\cdot g\cdot h\\\\p = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,6 \ m\\\\\boxed{p = 6 \ 000 \ Pa = 6 \ kPa}[/tex]
Siła nacisku:
[tex]p = \frac{F_{n}}{S} \ \ /\cdot S\\\\F_{n} = p\cdot S\\\\F_{n} = 6000 \ Pa \cdot0,5 \ m^{2} = 6000\frac{N}{m^{2}}\cdot0,5 \ m^{2}\\\\\boxed{F_{n} = 3 \ 000 \ N = 3 \ kN}[/tex]
