Oblicz wykonując skracanie jeśli to możliwe
Pls na teraz daje naj​


Oblicz Wykonując Skracanie Jeśli To MożliwePls Na Teraz Daje Naj class=

Odpowiedź :

b)

[tex] \frac{3}{5} \times \frac{15}{1} = \frac{3}{1} \times \frac{3}{1} = \frac{9}{1} = 9[/tex]

c)

[tex] \frac{36}{1} \times \frac{2}{3} = \frac{12}{1} \times \frac{2}{1} = \frac{24}{1} = 24[/tex]

d)

[tex] \frac{16}{1} \times \frac{1}{2} = \frac{8}{1} \times \frac{1}{1} = \frac{8}{1} = 8[/tex]

e)

[tex] \frac{3}{10} \times \frac{8}{1} = \frac{3}{5} \times \frac{4}{1} = \frac{12}{5} = 2 \frac{2}{5} [/tex]

f)

[tex] \frac{10}{1} \times \frac{11}{12} = \frac{5}{1} \times \frac{11}{6} = \frac{55}{6} = 9 \frac{1}{6} [/tex]

g)

[tex] \frac{4}{1} \times \frac{23}{10} = \frac{2}{1} \times \frac{23}{5} = \frac{46}{5} = 9 \frac{1}{5} [/tex]

h)

[tex] \frac{2}{1} \times \frac{25}{6} = \frac{1}{1} \times \frac{25}{3} = \frac{25}{3} = 8 \frac{1}{3} [/tex]

i)

[tex] \frac{8}{1} \times \frac{7}{4} = \frac{2}{1} \times \frac{7}{1} = \frac{14}{1} = 14[/tex]

j)

[tex] \frac{100}{1} \times \frac{127}{40} = \frac{5}{1} \times \frac{127}{2} = \frac{635}{2} = 317 \frac{1}{2} [/tex]

k)

[tex] \frac{49}{15} \times \frac{30}{1} = \frac{49}{1} \times \frac{2}{1} = \frac{98}{1} = 98[/tex]

l)

[tex] \frac{27}{25} \times \frac{125}{1} = \frac{27}{1} \times \frac{5}{1} = \frac{135}{1} = 135[/tex]

Myślę że pomogłem ;)

[tex]b) \ \frac{3}{5}\cdot15 = \frac{3\cdot15}{5} = 3\cdot3 = 9\\\\c) \ 36\cdot\frac{2}{3} = \frac{36\cdot2}{3} = 12\cdot2 = 24\\\\d) \ 16\cdot\frac{1}{2} = \frac{16\cdot1}{2} = 8\\\\e) \ \frac{3}{10}\cdot8 = \frac{3\cdot8}{10} = \frac{12}{5} = 2\frac{2}{5}\\\\f) \ 10\cdot\frac{11}{12} = \frac{10\cdot11}{12} = \frac{5\cdot11}{6} = \frac{55}{6} = 9\frac{1}{6}\\\\g) \ 4\cdot2\frac{3}{10} = \frac{4\cdot23}{10} = \frac{2\cdot23}{5} = \frac{46}{5} = 9\frac{1}{5}[/tex]

[tex]h) \ 2\cdot4\frac{1}{6} = \frac{2\cdot25}{6} = \frac{25}{3} =8\frac{1}{3}\\\\i) \ 8\cdot1\frac{3}{4} = \frac{8\cdot15}{4} = 2\cdot15 = 30\\\\j) \ 100\cdot3\frac{7}{40} = \frac{100\cdot127}{40} = \frac{5\cdot127}{2} = \frac{635}{2} = 317\frac{1}{2}\\\\k) \ 3\frac{4}{15}\cdot30 = \frac{49\cdot30}{15} = 49\cdot2 = 98\\\\l) \ 1\frac{2}{25}\cdot125 = \frac{27\cdot125}{25} = 27\cdot5 = 135[/tex]