Odpowiedź:[tex]10-\LEFT(2/3/11\cdot \:2/1/5\RIGHT)+\left(4/7\cdot \:4/2/3\right)=10-(\frac{2}{3}/11\cdot \:2/1/5)+(\frac{4}{7}\cdot \:4/2/3)=10-(\frac{2}{33}\cdot \:2/1/5)+(\frac{16}{7}/2/3)=10-(\frac{4}{33}/1/5)+(\frac{8}{7}/3)=10-(\frac{4}{165})+(\frac{8}{21})=\frac{11962}{1155}=10\frac{412}{1155}[/tex]
