Odpowiedź:
[tex]g)\\\\(x-4)(x+5)-x^2=3\\\\x^2+5x-4x-20-x^2=3\\\\x-20=3\\\\x=3+20\\\\x=23\\\\\\h)\\\\x^2-(x-3)(x-1)=1\\\\x^2-(x^2-x-3x+3)=1\\\\x^2-x^2+x+3x-3=1\\\\4x-3=1\\\\4x=1+3\\\\4x=4\ \ |:4\\\\x=1[/tex]
[tex]i)\\\\x^2-2=(x+2)(x+4)\\\\x^2-2=x^2+4x+2x+8\\\\x^2-2=x^2+6x+8\\\\x^2-x^2-6x=8+2\\\\-6x=10\ \ |:(-6)\\\\x=-\frac{10}{6}\\\\x=-1\frac{4}{6}\\\\x=-1\frac{2}{3}\\\\\\j)\\\\(x-3)(4x+2)=4x^2+3\\\\4x^2+2x-12x-6=4x^2+3\\\\4x^2-10x-4x^2=3+6\\\\-10x=9\ \ |:(-10)\\\\x=-\frac{9}{10}[/tex]
