Odpowiedź:
f(x) = x(x+3)^1/2
f'(x) = 1/2x(x+3)^-1/2 + 1
e)
f'(x) = u'*v-u*v'/v^2 = (-3 * 2x+7) -( 1 -3x * 2)/ (2x+7)^2
f)
f'(x)= u'*v-u*v'/v^2 = (2 * 5x^2 +1) - (2x+3 * 10x)/(5x^2+1)
g)
f(x)= 2x^3 * (2-3x)^1/2
f'(x)=u'v + uv'= 6x^2 *2-3x)^1/2 + 2x^3 *1/2(2-3x)^-1/2 * (-3)
