Odpowiedź:
[tex] \frac{{3}^{7} \times {2}^{7} + {2}^{2} \times {2}^{5} \times {3}^{7} }{ {6}^{8} } = \frac{ {6}^{7} \times + {2}^{7} \times {3}^{7} }{ {6}^{8} } = \frac{ {6}^{7} + {6}^{7} }{ {6}^{8} } = \frac{2 \times {6}^{7} }{ {6}^{8} } = \frac{2}{6} = \frac{1}{3} [/tex]
odp A
