oblicz 3/7+5/8, 4/9+1/3,2 3/4+ 5 2/5, 5 1/6 + 11 5/12

[tex]\frac{3}{7}+\frac{5}{8}=\frac{3\cdot8}{7\cdot8}+\frac{5\cdot7}{8\cdot7}=\frac{24}{56}+\frac{35}{56}=\frac{59}{56}=1\frac{3}{56}\\\\\frac{4}{9}+\frac{1}{3}=\frac{4}{9}+\frac{1\cdot3}{3\cdot3}=\frac{4}{9}+\frac{3}{9}=\frac{7}{9}\\\\2\frac{3}{4}+5\frac{2}{5}=2\frac{3\cdot5}{4\cdot5}+5\frac{2\cdot4}{5\cdot4}=2\frac{15}{20}+5\frac{8}{20}=7\frac{23}{20}=7+\frac{23}{20}=7+1\frac{3}{20}=8\frac{3}{20}\\\\5\frac{1}{6}+11\frac{5}{12}=5\frac{1\cdot2}{6\cdot2}+11\frac{5}{12}=5\frac{2}{12}+11\frac{5}{12}=16\frac{7}{12}[/tex]

АDAMiAKviz АDAMiAKviz · Answer 2

АDAMiAKviz АDAMiAKviz

przy dodawaniu lub odejmowaniu ułamków zwykłych należy sprowadzić je do wspólnego mianownika

[tex]a)\frac{3}{7}+\frac{5}{8}=\frac{24}{56}+\frac{35}{56}=\frac{59}{56}=1\frac{3}{56}[/tex]

[tex]b)\frac{4}{9}+\frac{1}{3}=\frac{4}{9}+\frac{3}{9}=\frac{7}{9}[/tex]

[tex]c)2,75+5,4=8,15=8 \frac{3}{20}[/tex]

[tex]d)5\frac{1}{6}+11\frac{5}{12}=5\frac{2}{12}+11\frac{5}{12}=16\frac{7}{12}[/tex]

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