Odpowiedź:
[tex]c)\\\\\frac{1,8x-\frac{5}{6}}{2}=\frac{2,3x+\frac{2}{3}}{5}\\\\5(1,8x-\frac{5}{6})=2(2,3x+\frac{2}{3})\\\\9x-\frac{25}{6}=4,6x+\frac{4}{3}\ \ |\cdot6\\\\54x-25=27,6x+8\\\\54x-27,6x=8+25\\\\26,4x=33\ \ |:26,4\\\\x=33:26,4\\\\x=33:\frac{264}{10}\\\\x=33:\frac{132}{5}\\\\x=\not33^1\cdot\frac{5}{\not132_{4}}\\\\x=\frac{5}{4}\\\\x=1\frac{1}{4}[/tex]
[tex]d)\\\\-1,8(\frac{2}{9}-0,5x)=\frac{5}{8}(4x+2,4)\\\\-\frac{18}{10}(\frac{2}{9}-\frac{1}{2}x)=\frac{5}{8}(4x+\frac{24}{10})\\\\-\frac{9}{5}(\frac{2}{9}-\frac{1}{2}x)=\frac{5}{8}(4x+\frac{12}{5})\\\\-\frac{\not9}{5}\cdot\frac{2}{\not9}+\frac{9}{5}\cdot\frac{1}{2}x=\frac{5}{\not8_{2}}\cdot\not4^1x+\frac{\not5^1}{\not8_{2}}\cdot\frac{\not12^3}{\not5_{1}}\\\\-\frac{2}{5}+\frac{9}{10}x=\frac{5}{2}x+\frac{3}{2}\ \ |\cdot10\\\\-4+9x=25x+15\\\\9x-25x=15+4\\\\-16x=19\ \ |:(-16)\\\\x=-\frac{19}{16}[/tex]
[tex]x=-1\frac{3}{16}[/tex]
