Odpowiedź:
a)
1 mol ---------- 22,4dm³
3,4 mola ------- x
x = 3,4 * 22,4dm³ : 1 = 76,16dm³
b)
[tex]M_{C_{2}H_{6} } = (2*12+6*1)\frac{g}{mol} = 30\frac{g}{mol}[/tex]
22,4dm³ ----------- 30g
x ------------ 480g
x=480g * 22,4dm³ : 30g = 358,4dm³
c)
Al₂S₃ - 54gAl + 96gS = 150g
[tex]150g_{Al_{2}S_{3} } - 96g_{S} \\675g_{Al_{2}S_{3} }-x\\x=432g_{S}[/tex]
32g ------- 6,02 * 10²³atomów
432g-------- x
x = 8,127 * 10²⁴
h)
[tex]M_{SO_{2} } = (32 + 16)\frac{g}{mol} = 48\frac{g}{mol}[/tex]
48g --------- 22,4dm³
x ---- 0,42dm³
x ≈ 0,89g
