Odpowiedź:
[tex]x-(4x-1)(x+3)=13-4x^{2} \\x-(4x^{2} +12x-x-3)=13-4x^{2} \\x-4x^{2} -12x+x+3=13-4x^{2} \\-4x^{2} -10x+3=13-4x^{2} \\-4x^{2} -10x+4x^{2} =13-3\\-10x=10 \ \ \ \ I:(-10)\\x=-1[/tex]
