a)
[tex]\frac{x+6}{2} = \frac{4}{3}\\\\3(x+6) = 4\cdot2\\\\3x+18 = 8\\\\3x = 8 - 18\\\\3x = -10 \ \ /:3\\\\x = -\frac{10}{3}\\\\\boxed{x = -3\frac{1}{3}}[/tex]
b)
[tex]Zal. \\x-4 \neq 0\\x \neq 4\\D = R \setminus\{4\}\\\\\frac{5}{x-4} = \frac{3}{2}\\\\3(x-4) = 5\cdot2\\\\3x - 12 = 10\\\\3x = 10+12\\\\3x = 22 \ \ /:3\\\\x = \frac{22}{3}\\\\\boxed{x = 7\frac{1}{3}}[/tex]
c)
[tex]\frac{1}{3}=\frac{x-7}{6}\\\\3(x-7) = 6 \ \ /:3\\\\x-7 = 2\\\\x = 2+7\\\\\boxed{x = 9}[/tex]
