Odpowiedź:
wysokość trójkąta równobocznego to [tex]h = \frac{a \sqrt{2} }{3} [/tex]
[tex]1.5 = \frac{a \sqrt{2} }{3} \: \: \: \: \: | \times 3 \\ 4.5 = a \sqrt{2} \: \: \: \: \: | \div \sqrt{2} \\ a = \frac{4.5}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ a = \frac{4.5 \sqrt{2} }{2} = 2.25 \sqrt{2} [/tex]
P=[tex] \frac{a \times h}{2} [/tex]
P=
[tex] \frac{2.25 \sqrt{2} \times 1.5}{2} = \frac{3.375 \sqrt{2} }{2} = 1.6875 \sqrt{2} [/tex]
