Odpowiedź:
[tex]e)\\\\\frac{x}{-3}\leq 1\ \ |\cdot(-3)\\\\x\geq -3\\\\\\f)\\\\-2(1+x)\geq 2\\\\-2-2x\geq 2\\\\-2x\geq 2+2\\\\-2x\geq 4\ \ |:(-2)\\\\x\leq -2\\\\\\g)\\\\\frac{4x}{-5}>-3\ \ |\cdot(-5)\\\\4x<15\ \ |:4\\\\x<\frac{15}{4}\\\\x<3\frac{3}{4}\\\\\\h)\\\\\frac{-2x}{7}<-2x\ \ |\cdot7\\\\-2x<-14x\\\\-2x+14x<0\\\\12x<0\ \ |:12\\\\x<0[/tex]
