Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]2x+5y-8z=8\\4x+3y-9z=7\\2x+5y-8z=8\\x+8y-7z=12\\\\-7y+7z=-9\\-11y+6z=-16\\\\y=\frac{58}{35} \\\\z=\frac{13}{35}\\\\\\x+8*\frac{58}{35}-7*\frac{13}{35}=12\\x=\frac{47}{35}\\\\2*\frac{47}{35}+5*\frac{58}{35}-8*\frac{13}{35}=8\\\\4*\frac{47}{35}+3*\frac{58}{35} -9*\frac{13}{35}=7\\\\\frac{47}{35}+8*\frac{58}{35}-7*\frac{13}{35}=12 \\\\\\8=8\\7=7\\12=12\\\\(x,y,z)=(\frac{47}{35}, \frac{58}{35}, \frac{13}{35}[/tex]
