Matematyka klasa 7
Prosze o pomoc w zadaniu

(1/5)^9÷(4/25)^9
----------------------
1,25^8

Te kreski (-----) to chodzi mi ze to jest w ulamku wszystko


Odpowiedź :

[tex]\dfrac{(\dfrac{1}{5} )^{9}\div (\dfrac{4}{25} )^{9} }{1,25^{8} } =\dfrac{(\dfrac{1}{5}\div \dfrac{4}{25} )^{9} }{(1\dfrac{25}{100} )^{8} }=\dfrac{(\dfrac{1}{5}\cdot \dfrac{25}{4} )^{9} }{(1\dfrac{1}{4} )^{8} }=\dfrac{(\dfrac{5}{4} )^{9} }{(\dfrac{5}{4} )^{8} }=\dfrac{(\dfrac{5}{4} )^{9} }{(\dfrac{5}{4} )^{8}} =(\dfrac{5}{4} )^{9} \div (\dfrac{5}{4} )^{8}=(\dfrac{5}{4} )^{9-8}(\dfrac{5}{4} )^{1}=\dfrac{5}{4} =1\dfrac{1}{4} =1,25[/tex]

korzystam ze wzorów:

[tex]x^{n} \div y^{n} =(x\div y)^{n} \\\\\dfrac{x^{n} }{x^{m} } =x^{n} \div x^{m} =x^{n-m}[/tex]