[tex]dane:\\p_{h} = 5 \ 000 \ hPa = 500 \ 000 \ Pa\\d = 1\frac{g}{cm^{3}} = 1000\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\szukane:\\h = ?\\\\Rozwiazanie\\\\p_{h} = d\cdot g\cdot h \ \ /:(d\cdot g)\\\\h = \frac{p_{h}}{d\cdot g}\\\\h = \frac{500 \ 000 \ Pa}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}}=\frac{500 \ 000 \ \frac{N}{m^{2}}}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}}\\\\\boxed{h = 50 \ m}[/tex]
